<p>If >x = X + 1/X for all nonzero integers z. If >x = t, where t is an integer, whch of teh following is a possible value of t.</p>
<p>A. 1
b. 0
c. -1
d. -2
e. -3</p>
<p>how is the answer -2?????????</p>
<p>If >x = X + 1/X for all nonzero integers z. If >x = t, where t is an integer, whch of teh following is a possible value of t.</p>
<p>A. 1
b. 0
c. -1
d. -2
e. -3</p>
<p>how is the answer -2?????????</p>
<p>bump please help.</p>
<p>is >x, greater than x or a variable separate from x on the other side…</p>
<p>just a variable separate on the other side.</p>
<p>If I am reading you correctly, then this is a “made-up-symbol” problem. Easiest way is to try putting in some numbers and see what you get…</p>
<p>Soon, you will notice that when you put in any non-zero integer, you get a mixed number out…except if you use 1 or -1. 1 + 1/1 =2 but that’s not on the list.</p>
<p>-1 + 1/-1 = -1 + -1 = -2. And that is on the list.</p>
<p>OMG pckeller wow i was using a possible value of x. ur so smart. may u get karma points!</p>