<p>It's from a free Princeton Review practice test I took a few months ago. No one in my family can figure it out, and it's driving me insane. Can anyone explain how to do it?</p>
<p>1A</p>
<h2>x B3</h2>
<p>BA</p>
<h2>+ 60</h2>
<p>6BA</p>
<p>In the operation above, A and B represent distinct digits. What is the value of A + B?
The answer is 9.</p>
<p>Is 6BA a 3 digit number or 6 * BA?</p>
<p>I really don’t know, which is why I’m so confused. It can’t be a 3 digit number, because it’s impossible to get 600 something from adding two 2 digit numbers. But having multiplication there also seems odd to me.</p>
<p>I think there’s an error… I don’t see how you can multiply two two-digit numbers and still get a two digit number as your result…
For example, 10x10 = 100, 99x99 = 9801
So one of the numbers has to NOT be a two digit number, leaving B because it has the B3 thing. But if B was zero then the whole result would end up with a 0 in the tens place which would be impossible.
I don’t think that made any sense but oh well</p>
<p>1A has to be between 10 and 19: 10, 11, 12, 13, 14, 15, 16, 17, 18, 19
And be has to end in 3. 13, 23, 33, 43, 53, 63, 73, 83, 93</p>
<p>The last two digits need to equal 9, right? (A+B)</p>
<p>Combinations: (9,0); (6,3); (5,4); (7,2); </p>
<p>We can eliminate all but 6,3. </p>
<p>And nothing works out. Is this a CB question?</p>
<p>
Its from PR, as stated in the OP’s post</p>