<p>Most sample surveys use random digit dialing equipment to call residential telephone numberse at random. The telephone polling firm Zogby International reports that the probability that a call reaches a live person is 0.2. Calls are independent.</p>
<p>a. A polling firm places 5 calls. What is the probability that none of them reaches a person?</p>
<p>This is what I did: 1- .2^5=.99968
On the other hand, this is what the book did: .8^5=.32768</p>
<p>I don't see why the way I did it doesn't work. Any help?</p>
<p>you are trying to see the probability of NOT getting a live person the first time, then NOT getting one a second time, then NOT a third, fourth, etc. The probability of getting someone is .2, therefore, probability of NOT getting someone is .8. If you want to NOT get someone 5 times in a row, you need to multiply .8 by itself 5 times.</p>
<p>.8^5</p>
<p>What you are doing is subtracting .2^5 from 1 which doesn't seem to make much sense to me</p>