<p>Consider the differential equation dy/dx=-2x/y</p>
<p>a) Let y=f(x) be a particular solution to the differential equation with the initial condition f(1)=-1. Write an equation for the line tangent to the graph of f at (1,-1) and use it to approximate f(1.1).</p>
<p>b) Find the particular solution y=f(x) to the given differential equation with the initial condition f(1)=-1.</p>
<p>At first I just separated the variables, took the derivative and came up with the general solution y=sqrt(c-2x^2). Then I solved for C and found it to be 3. But now I realize that is the answer to part b not part a. I'm confused what I even do for part a. How to I find the tangent line?</p>