<p>hey guys i got stuck.</p>
<p>An object with a mass m = 1.0 kg is moving horizontally with a velocity of 10 meters per second, as shown above, when it makes a glancing collision with the lower end of a bar that was hanging vertically at rest before the collision. For the system consisting of the object and bar, linear momentum is not conserved, but kinetic energy is. The bar, which has a length l of 1.2 meters and a mass M of 3.0 kg, is pivoted about the upper end. Immediately after the collision the object moves with a speed v at an angle theta relative to its original direction. The bar swings freely, and after the collision reaches a maxium angle of 90 degrees with respect to the vertical. the moment of inertia of the bar about the pivot is I = (ml^2)/3. Ignore all friction.</p>
<p>Determine the angular velocity of the bar immediately after the collision, and the speed v of the 1 kg object immediately after the collision.</p>
<p>so i know to set up the KE of the object before collision equal to the KE of the object after the collision + KE of the bar, but now im stuck. any help?</p>