<p>My math is like 100 points below reading and writing... help with these 2 please?</p>
<p>A regulation for riding an amusement park ride requires that a child be between 30 and 50 inches tall. Which inequality can be used to determine if a child (height h) can go on the ride?</p>
<p>absolute value (h-10)<50
abs(h-20)<40
abs(h-30)<20
abs(h-40)<10
abs(h-45)<5</p>
<p>I thought it was c, because you can write 30<h<50, minus 30 from the whole thing and you get h-30<20... but that's wrong. I don't get why.</p>
<p>Ok so the second problem involves a picture which I'm too lazy to draw so never mind, lol. It's #16 on test 5, section 8 of the SAT big blue book if anyone wants to help me out :) thanks in advance!</p>
<p>for the first one it is “D” because the absolute value will split the inequality into two equations!! h-40<10 and h-40>-10 then you simply get the h on one side so you have h<50 and h>30.</p>
<p>For the second problem, I would first start out by converting all sides of the drawn rectangle into terms of L. Since a rectangle’s opposite sides are equal, 3W = 2L or W = 2/3L. A 12L units long pattern would have six of these rectangles stacked on top of each other and a 10L units wide long pattern would have 10/(5/3) or 6 rectangles put side by side. This means that there are 36 rectangles like the ones in the picture in the entire pattern. Since each rectangle like the one in the picture has 5 L X W rectangles, there are 180 rectangles in total.</p>
<p>KingUncaged1, but how do you know to write the inequality as h-40<10 in the first place…? I mean to me, it seems that since the child has to be between 30 and 50 inches, you’d do something with those numbers to make the equation…?</p>
<p>bio19950- THANK YOU! You’re explanation was so much better than the blue book’s, lol. I get it now :)</p>
<p>Since the child must be between 30 and 50, its distance from 40 must be less than 10. The absolute value of something is its distance from zero. Thus, the distance of x-40 must be less than 10.</p>