<p>If t is an integer, t > 2, and z = t + (2/t), which of the following must be true?</p>
<p>I. z does not equal t
II. z is an integer
III. z > t ^ 2</p>
<p>A. I only
B. III only
C. I and II only
D. I and III only
E. I, II, and III </p>
<p>Answer: D</p>
<p>Can someone explain this question to me?</p>
<p>Okay,</p>
<p>I. This is true: Set up an equality with z=t: t = t + 2/t, which doesn’t work (2/t =/= 0 when t is an integer)</p>
<p>II. This is not true. “t” will always be an integer, but “2/t” will always NOT be an integer. This is because t>2, so 2/t will always be less than 1.</p>
<p>III. What is iz? I don’t think we’re dealing with complex numbers here…</p>
<p>oops… i mean
III. z > t ^ 2</p>
<p>12love,u mean z<t^2,right?..if u=“” don’t=“” mean=“” that,then=“” i=“” have=“” any=“” answer=“” for=“” you…under=“” no=“” circumstances=“” z=“”>t^2 when z is an integer is possible…recheck the answer choices and tell us from where did you find it?</t^2,right?..if></p>
<p>I don’t think III is true… z will be less than t^2. Think about it when you plug in t=4:</p>
<p>z = 4 + 2/4 = 4.5
t^2=16</p>
<p>baelor,it’s also true when u plug 3 for t</p>
<p>i think the answer choice is lll.z<t^2</p>
<p>I made another mistake. So sorry!!</p>
<p>III. tz > t ^ 2</p>
<p>"baelor,it’s also true when u plug 3 for t</p>
<p>i think the answer choice is lll.z<t^2"</p>
<p>Obviously. But we only need one counterexample to disprove it.</p>
<p>Okay, 12love:</p>
<p>III. t(z) = t(t+2/t) = t^2 + 2 > t^2, obviously. Yay!</p>
<p>For this one, plug in a number. Itll be true for alll numbers.</p>
<p>So the answers D?</p>
<p>yup. it says it in original post</p>