<p>I need help with some question in the SAT Blue book, id really appreciated if someone here could help me in some if not all.</p>
<p>Section 3:17 i thought it was A because it equaled -3
Section 6:7,16
Section 9:12</p>
<p>which book? which test?</p>
<p>Which one?? BB OR BB2</p>
<p>Ohh sorry, BB and the second test.</p>
<p>bump…</p>
<p>17) the answer is A. what is the conflict?</p>
<p>7)</p>
<p>anything in the radical can be factored out
18=6<em>3
√18=(√6)</em>(√3)
18=9<em>2
√18=(√9)</em>(√2)</p>
<p>you have to find a factorization that allows you to simplify one of the factors
in the last example, √9 = 3
so, √18 = (√9)*(√2) = 3√2</p>
<p>going back to the problem
18 √18 = r√t
18(3√2) = r√t
54√2=r√t</p>
<p>r is 54 and t is 2
rt is 108, which is the answer C</p>
<p>16)
h(x) = 14 + (x^2)/4
h(2m) = 9m</p>
<p>x=2m, you plug in 2m for x</p>
<p>h(x): x is being squared in the term (x^2)/4
h(2m): 2m is being squared in the term (2m)^2 / 4</p>
<p>h(2m) = 14 + (2m)^2 / 4
square the 2 and the m, you get 4 and m^2
h(2m) = 14 + 4m^2 / 4
h(2m) = 14 + m^2</p>
<p>14+m^2 = 9m
subtract 9m from both sides
m^2 - 9m + 14 = 0
factor this.
(m-7)(m-2) = 0
check if the factoring is correct. (-7)(-2)=14, (-7)+(-2)= -9</p>
<p>if m=7, then the equation equals 0… (7-7)(7-2)=0<em>5=0
if m=2, then the equation equals 0… (2-7)(2-2)= -5</em>0=0</p>
<p>2 or 7 are the answers</p>
<p>12)</p>
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<p>x+y=4
2x+2y=8</p>