<p>I don't understand why part j would be false. If someone could explain it to me that would be great. Thanks!</p>
<p>
</a></p>
<p>So it is saying that the limit of f(x) (the graph) as x approaches 2 from the left is equal to 2. That is, as the x value is approaching 2, the y value is approaching 2. In the graph, you can see that as the x value is approaching 2, the y value remains constant at y = 0. Therefore, the limit of f(x) as x approaches 2 from the left is actually equal to 0.</p>
<p>Be sure to remember that the value on the other side of the equals sign is the y value that the graph/function is approaching.</p>
<p>Oh I get it now, thank you! Would you happen to know what they are asking about on part h and I of this problem?</p>
<p>
<a href=“http://tapatalk.com/mu/4b20c81b-bdf3-721d.jpg[/IMG]”>http://tapatalk.com/mu/4b20c81b-bdf3-721d.jpg
![http://tapatalk.com/mu/4b20c81b-bdf3-721d.jpg[/IMG]](http://tapatalk.com/mu/4b20c81b-bdf3-721d.jpg%5B/IMG%5D){kind=link}
</a></p>
<p>Yes, they are asking if a limit exists for every value of x in the intervals. If you plug in the x value into c for every point in the given intervals, does a limit exist?</p>