Help with x√x problems

<p>I must have missed the day roots were taught, because I remember nothing.</p>

<p>Here is the problem: 5√2 + √2 - (√2)2</p>

<p>Can someone walk me through the process? Thanks!</p>

<p>y dont you jjust plug it in…?</p>

<p>^ :S Plug what in? There are no variables.</p>

<p>Just factorise the expression by taking √2 common:</p>

<p>…5√2 + √2 - (√2)2
=√2 (5 + 1 - 2)
=4√2</p>

<p>Treat √2 as a variable and think of the the number in front of it as a coefficient that can be added. 5+1-2 = 4. So 4√2.</p>

<p>so that’s what dipole meant by plugging in…</p>

<p>I understand now. Thanks!</p>