<p>
</a></p>
<p>I have tried to choose this b, but the right answer is c. I don't know how?</p>
<p>//Ignore this</p>
<p>Sorry I realized something. It should be D. Anyone else agree? I thought C was D, and vice versa, so I told C in my above reply. The circumference of the circle is 16pi. Divide that by 4 to get the length of the curve, which is 4pi. Then add the two remaining sides, which are radii, to get 16. So the final answer is 4pi+16. I don't know how it could be c, but if you picked b I think you forgot to add 8+8.</p>
<p>I still do not understand what are two remaining sides?</p>
<p>the two remaining sides are the two radii. You were taking into account only the curve. 8+8+4pi... answer d is correct.</p>
<p>Oh, I understand, do you think this sort of question is a bit hard. I find it quite tricky. Though I totally admit that I carelessly forget to add up 16.
However, thanks, iin77 and gk23.</p>
<p>
</a></p>
<p>Can anyone helps me with this? Thanks</p>
<p>nvm, misread, sec, lol</p>
<p>I got E.</p>
<p>Hard to explain geometry without a diagram, but I'll try:</p>
<p>On the other side of line CD, the angle equals 180-x, so one half of angle C = 180-y-(180-x) = 180-1/3x-180+x = 2/3x. The other half of angle C is also 2/3x (because CD bisects angle C). so z = 180-x-2/3 = 180-5/3. And since AB=BC, that means ABC is isosceles, so z = 2/3x *2 = 4/3x</p>
<p>by substitution, 180-5/3x=4/3x x=60, so z=80</p>
<p>Oh, I get you. I imagine the first part 180-x and C=180-y-(180-x), but then stumble upon other parts.</p>
<p>Thanks</p>
<p>Is it OK if I take this threat to be a frequent one for asking questions?</p>
<ol>
<li><p>n is an integer chosen at random from the set</p>
<p>{5, 7, 9, 11 }</p></li>
</ol>
<p>p is chosen at random from the set</p>
<pre><code>{2, 6, 10, 14, 18}
</code></pre>
<p>What is the probability that n + p = 23 ?</p>
<p>A. 0.1
B. 0.2
C. 0.25
D. 0.3
E. 0.4 </p>
<p>Can anyone help, thanks</p>
<p>first, you find the total number of combinations of numbers chosen (one from each set) that equals 23. This would be (5,18) and (9,14). Then you find the total number of combinations: 4 * 5 = 20 2/20=.1
Answer is A.</p>
<p>OK, make sense. Probability is my weakness actually.</p>
<p>Mmhmm, keep posting questions, because I'm bored and AIM isn't working, lol.</p>
<p>In the first one the correct answer is D.</p>
<p>The circumference of a circle is (2 x Pi x Radius), hence the circumference of a quarter circle is that divided by for (2 x Pi x Radius) / 4</p>
<p>You have the info that Radius is 8</p>
<p>So (2 x 8 x Pi) / 4 is 16 Pi / 4. Result is 4pi. But that is the perimeter of the curve area, you are missing the two lines that join the center with the curved part (the radius) so if you have two radius, and each radius is 8, two radius are 16.</p>
<p>That's why the anwser is 4Pi + 16</p>
<p>
</a></p>
<ol>
<li>A and B are equidistant from the line l. How many circles can be drawn with their centres on line l and that pass through both A and B?</li>
</ol>
<p>A. 1
B. 2
C. 3
D. 4
E. >10</p>
<p>BTW, most of the questions I get wrong is word questions. Any advice? Since English in Math is more taunting than English in CR.</p>
<p>Thanks though
c0calait</p>
<p>Cuong, I think the answer to the question number 9 is option A.</p>
<p>I'm not sure, but I hope someone better than I posts the answer.</p>
<p>Actually I have worked out. It is E
Know why, it is logic and quite abstract. I always imagine line l as the radius of an imaginative circle. So, no matter how far you move away from the line AB, these circles just overlap each other. The father away you move, the bigger the circle is. So it is actually "moving nowhere".</p>
<p>Limitless circle is the final answer. I like these sorts of question.</p>
<p>But you know what, very rare could one find such an above question. I might not put too much intension upon that.</p>
<p>
</a></p>
<p>
</a></p>
<p>Again, I stumbled upon this.
My math too weak, I am going to dumb this Dec test just like the Oct</p>