<p>OK, thanks, let's me revise it again</p>
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<p>For this one, let me set out my solution whether it appeals to you, since I don't have the answer sheet for this question.</p>
<p>The Area of Rectangle = lw
The Area of the eclipse = pi.l.w/4 = 7pi
from the equation above, if I can calculate lw then there is nothing to worry.
lw = 28
hence the unshaded area = 28 - 7pi equal approximately 6</p>
<p>Is that correct?</p>
<p>Yup, that's right.</p>
<p>OK, next</p>
<p>(T . 3^3) + (U . 3^2) + (V . 3) + W = 50</p>
<p>What is TUVW represents for??</p>
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<p>This one I get (A), right?</p>
<p>it's b. side of square is radius/sqrt(2) = 3. Perimeter=3*4=12.</p>
<p>d, side of square is diameter/sqrt(2)</p>
<p>?? I don't understand</p>
<p>I also have a 12 which is b.
How do you get d snipez90</p>
<p>i think it's B also</p>
<p>Next, this one is quite hard to me.</p>
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<p>the answer to the first question on this page is D</p>
<hr>
<p>(3 * sqrt(2)) * 2 is the diagonal of the square.</p>
<p>pythagoras</p>
<p>(6 * sqrt(2)) ^ 2 = x^2 + x^2
36 * 2 = 2x^2
72/2 = x^2
sqrt (36) = x
6 = x</p>
<p>You get that one side of the square is 6, hence the perimeter is 6*4 = 24</p>
<p>The answer is D to the first question of this page. </p>
<p>The radius is said to be 3squareroot(2). The diagonal there for is
2<em>3squareroot(2). Now it's all about knowing your triangle principles. Since the triangle is 45/45/90, the sides HAVE to be 6 since the hypotnuese is 6squareroot(2). We have 4 sides that equal 6 and so the answer is 4</em>6=24</p>
<p>Oh I understand now, thanks a lot. Diameter and Radius needs to be paid much more attention.</p>
<p>Please help me the second question.</p>
<p>B, let r be the radius of the smaller circle, which also happens to be half the length of a side of the square. From this, we get that the shaded area is</p>
<p>Area of square - Area of smaller circle = (2r)^2 - (pi)r^2. Now we have the shaded area, we have to find all possible points which is the same as the area of the larger circle. Draw a line from the center of the circles to a corner of the square, this line is the radius of the larger circle and its length is given by r*sqrt(2) so the area of the larger circle is 2(pi)r^2.</p>
<p>The probability is the shaded area over the area of the larger circle or 4r^2 - (pi)r^2 divided by 2(pi)r^2. Dividing out the r^2 gives us choice B.</p>
<p>Sounds a bit complicated, can you explain me more
BTW, do you have any tip to deal with Probability?</p>
<p>draw a line going from the center of the smaller circle (which is also the center of the larger circle) directly above to the point where the square and the smaller circle touch at one point. Is it clear that this is the radius of the smaller circle and is also equal to half the length of the square?</p>
<p>Now draw a line going from the center of the smaller circle to the top-right corner of the square where the square touches the larger circle. Does it make sense that this line is the radius of the larger circle?</p>
<p>In probability problems, we are looking for two essential parts: the desired outcome and the total number of outcomes. The actual answer is the desired outcome divided by the total possible outcomes. In this case, it's easy to see that the desired outcome is the shaded area. Now finding the total possible outcomes requires a little common sense. The part of the question that says "if a point on the figure is chosen randomly..." tells us that we are to choose a point within the boundaries of this figure. In other words, the total number of points on this figure make up our total number of outcomes. So essentially, we're trying to find the set of points on and within the larger circle, which is also the area of the larger circle. So our probability is: area of shaded region / area of larger circle</p>
<p>Now see if you can piece together everything and get the answer. You should be able to find the area of the shaded region pretty easily now. I'll leave the radius of the larger circle to you to figure out.</p>
<p>Kind a get it, thanks, I shall work it again upon my own. Only this way can I understand it</p>
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<p>Thanks, gentlemen.</p>