Hmm, can someone explain these questions to me?

Test Preparation SAT Preparation
1

<li>The sqaure of x is equal to 4 times the square of y. If x is 1 more than twice y, what is the value of x?</li>
</ol>

<p>(A) -2
(B) -1/2
(C) - 1/4
(D) 1/4
(E) 1/2</p>

<p>Answer: E</p>

<li>In the xy-coordinate plane, lines l and q are perpendicular. If like l contains the points (0, 0) and (2,1) and line q contains the points (2, 1) and (o, t), what is the value of t?</li>
</ol>

<p>(A) -3
(B) -2
(C) 2
(D) 3
(E) 5</p>

<p>Answer: E</p>

<li>If 3x + y/y = 6/5, what is the value of x/y?</li>
</ol>

<p>Answer: .067, .066, 1/15</p>

<p>I know that you can cross multiply, but I used the simpler route and noticed that x = 1/3 and y = 5.</p>

<p>Afterwards, I did 1/3 / 5 (x/y) which is 5 / 3 when you flip 3/5. But by x /y, they meant dividing the values regularly. Didn’t I do the same? I know what I’m asking is confusing, but bluntly: How do I know which way to exactly divide the fractions in questions like this?</p>

<li>Mediators were standing by, prepared to intervene in the labor dispute even though both sides had refused earlier offers for assistance No error</li>
</ol>

<p>Error: “For”</p>

<p>Why?</p>

<p>Thanks!</p>

2

<p>I think the Error "for" should be "in"</p>

3

<ol>
<li><p>I get y=-1/4. Can you show us how you get E?</p></li>
<li><p>Did you by some chance mean (0,t) instead of (o,t)?</p></li>
<li><p>Since y/y is 1, and y can be number short of infinity, how can you possibly have a value for x/y?</p></li>
<li><p>How about "of" instead of "for"?</p></li>
</ol>

4

<p>Yeah, sorry, I meant (0, t)</p>

<p>As for 19, I'm basing this off of the answer key I have, which says E. </p>

<p>For the grammar question, I wanted to know why for is wrong. Is it because it isn't idiomatic? If so, then what is?</p>

5

<p>anyone....?</p>

6

<p>Should be "offer of"</p>

7

<p>first one:</p>

<p>x^2=4y^2
x=2y+1</p>

<p>use substitution and put the 2nd equation into the first for x:
(2y+1)^2=4y^2</p>

<p>4y^2+4y+1=4y^2</p>

<p>4y=-1</p>

<p>y=-1/4
plug that into the second equation and solve for x</p>

<p>x=2(-1/4)+1
=-1/2+1
=1/2</p>