<p>Okay, this sounds ridiculous, but I can't seem able to figure it out....I know what to do, I just can't figure it out! It has me frustrated.
</a></p>
<p>Okay, this sounds ridiculous, but I can't seem able to figure it out....I know what to do, I just can't figure it out! It has me frustrated.
</a></p>
<p>Oh, c'mon.</p>
<p>One way to do this would be to graph the lines, find the intersection point, and then use that and some mathmagic to find the area.</p>
<p>You can also consider similar triangles (with the right triangles).</p>
<p>Those were the two ways that I thought of off the top of my head. I'm sure there are more.</p>
<p>Or, find the area of ABCD and subtract from it the areas of AED and EBFG. Area of AED is simple. For area of EBFG, draw a line from G perpendicular to side BF. Call that point X. Then, find the area of right triangle GXF (first you have to find what point G is). You're left with the area of trapezoid EGXB.</p>