How do you do this Math question?

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1

<p>R 2 R
+6 T 9</p>

<hr>

<p>T R 0</p>

<p>What is T?</p>

<p>Choices:
A. 1
B. 6
C. 7
D. 8
E. 9</p>

<p>The answer is choice D, but that doesn't make any sense. If T is 8, then R would be 0, and R can't be zero otherwise the units digit of the result wouldn't be 0, it would be 9.</p>

2

<p>Another few:</p>

<p><a href=“College Board - SAT, AP, College Search and Admission Tools”>College Board - SAT, AP, College Search and Admission Tools;
Question 17, 20, 22, and 23 Section 2</p>

3

<p>Nope. I started by picking numbers for R and started with the simplest, which is 1.
1 2 1

  • 6 T 9
    = T 1 0</p>

<p>1+9=10, carry the 1.
1+2+T= 1, 11, or 21 (something with a 1 in the ones place). 1 is out of the question, but if T=8, 1+2+8=11. I went off that to see if it worked out.
Carry the 1, so 1+1+6=T=8. </p>

<p>If you’d picked a different number for R is just wouldn’t have worked out that T=the same number both times and you’d had to have picked a different number. Another strategy might be to pick numbers for T instead, seeing how they’re listed in front of you.</p>

4

<p>If T is 8, R doesn’t have to be zero. If R is not zero, the smallest integer greater than zero is 1. Then 1+9=10 and you carry the one over one place to the left. Since the last digit of the answer is 0, R would have to be 1. If T is 8 and R is 1, the equation should be 121+689 which is equal to 810.</p>

5

<p>When I said that if T = 8, then R would be 0, it’s because 2 + T in the second column would translate to 2 + 8, which is 10, and that means R would be 0, because R is the result of 2 + T. But obviously R can’t be 0, otherwise R + 9 would be 9.</p>

6

<p>That’s untrue because you’re not starting with the third column. In addition you always start on the right. 1+9=10. You have to carry the 1 to the second column. Therefore the second column reads 2 + T +1 (carried over), which equals 11. The ones place digit is what R is equal to, so R equals 1 when you start from the right.</p>

7

<p>Nevermind. I didn’t realize that something could be carried over to 2 + T and that it doesn’t have to end up in 0. Thanks for the help. </p>

<p>Anyone know how to solve these?
<a href=“College Board - SAT, AP, College Search and Admission Tools”>College Board - SAT, AP, College Search and Admission Tools;
Question 17, 20, 22, and 23 Section 2</p>