<p>A circle with a radius of 2 is superimposed upon a squae with sides measuring 5 so that the center of the circle and the center of the square are identical. At how many points will the square and circle intersect?</p>
<p>This is not a MC question</p>
<p>0 points of intersection.
The longest chord that can be made in this circle is the diameter with a length of 4 units.
Since the square has sides with a length of 5 units, and it has the same center point of
the circle, it is impossible for them to intersect, since 4 < 5.</p>
<p>The only squares that can intersect the circle any points would be
squares with sides that have the lengths 2 < s < 4 and have the same center
of the circle.
s is the length of the square.</p>
<p>This is a question that tests to see if you can think abstractly.
Try drawing the image to help you "see" what the question is asking.</p>