How do you solve this problem?

Test Preparation SAT Preparation
1

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<a href="http://imgur.com/Nuo9b.jpg%5B/img%5D"&gt;http://imgur.com/Nuo9b.jpg

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2

<p>assign a value of 10 to QR. then find 2/5 of 10 (which equals 4). Now you know that PT = 4 and TS = 6. 1/2 * b * h can be used to find the base of the triangle. 1/2 * b * 6 = 7. (solve for b which is 7/3). then do 7/3 * 10. and your answer = 70/3.</p>

<p>i think. that is how i would do it.</p>

3

<p>Okay so write down everything you know.</p>

<p>Area Rect = (PS)(SR)
If PT = 2/5(PS) then TS = 3/5(PS)
So…
Area Tri = (1/2)(3/5*PS)(SR)</p>

<p>^That equals 7 so
7 = (1/2)(3/5*PS)(SR)
= (3/10)(PS)(SR)</p>

<p>Now, because you know that Area Rect = (PS)(SR) , just solve for (PS)(SR) in ^ that equation. So
70/3 = (PS)(SR)
= Area of Rect.</p>

4

<p>70/3 is correct. Does assigning values like that usually work on the SAT? I got 70/3 would be for SR and knew I had to be doing something incorrectly.</p>

<p>What about this problem?
<a href=“http://i53.■■■■■■■.com/2qx3o6v.jpg[/url]”>http://i53.■■■■■■■.com/2qx3o6v.jpg&lt;/a&gt;
How do you go about solving that?</p>

5

<p>lol i did differently. I just mirrored the triangle along RT to give me a rectangle with area 14. which is 3/5 of the total area. To get the total area divide by 3 times 5 to give me 70/3.</p>

6

<p>Did it similar to others here. After using the fact that PT was 2/5 of PS, that just meant we had 3/5 left. Plugging into the formula: A = (1/2)(B)(H), 7 = (1/2) (3/5) (H).</p>

<p>7 = 3/10H
70/3 = H</p>

<p>Area of a Rectangle is l*w, so 1 x 70/3 = 70/3.</p>

7

<p>usenamo, is the answer B?</p>

<p>I’d list out all the factors of 12. 1,2,3,4,6,12. You could first of all factor p^2-n^2 into (p-n)(p+n) = 12.</p>

<p>Since p > n > 0, </p>

<p>12 23 34 46 12
13 24 36 412
14 26 312
16 212
12</p>

<p>Note: I wrote these in reverse order, so read this as (2-1)(2+1), etc etc. My bad.</p>

<p>If we can’t get a combination of the factors of 12, then we’re screwed. If P+N>12, we can’t use it. However, the factors between 6< P+N<12: 7, 8, 9, 10, 11 will not yield something we can work with either. Since the only factor we can use to make (P-N)(P+N) = 12 is 1(12), we can also discard it. And 4<P+N<6 we can also not use because it’s not a factor of 12. </p>

<p>21<br>
31
42 </p>

<p>Unreversed it for this step…You can tell right off the bat that (2-1)(2+1) and (3-1)(3+1) isn’t going to be 12. The answer I’ve only found that works is (4-2)(4+2) = 12. </p>

<p>So although most of this occurred to me in my head in split seconds, you basically force (P-N) to be one of those numbers.</p>

<p>4(P+N) = 12.
2(P+N) = 12.
1(P+N) = 12. </p>

<p>P+N = 3 has to be 2+1, which means P- N is 1, which 3(1) does not equal 12.
P+N = 6 can be 4+2, not 3+3 cause p>n, not 2+4 because p>n, not 5+1 because (5-1)(5+1) doesn’t equal twelve.
P+N = 12. This shouldn’t have to be explained.
2(6) = 12.</p>

8

<p>You are correct, the answer is B.</p>