How the hell do you solve this?

<ol>
<li>If x2 + y2 = 14 and xy = 3, then (x + y)2 =</li>
</ol>

<p>(A) 11
(B) 17
(C) 20
(D) 24
(E) 28</p>

<p>so stumped...</p>

<p>x^2 + y^2 + 2xy = (x+y)^2
Hence, 14 +6 = (x+y)^2
Hence the answer is 20</p>

<p>thank you so much</p>