<p>For all numbers x, let #x be defined as #x = -x + 1. Which of the following is equal to #(#x) ?</p>
<pre><code>* x
* x + 1
* x + 2
* -x + 1
* -x + 2
</code></pre>
<p>sat skills insight
communication :the origin problem</p>
<p>representation: the g(x) and the f(x) problem</p>
<p>can you guys help explain these?</p>
Mondo
November 30, 2008, 1:26pm
2
<ul>
<li>(-x+1) +1</li>
</ul>
<p>x-1+1=x</p>
<p>So the answer is *x.</p>
Mondo
November 30, 2008, 1:28pm
3
<p>Since #x= -x+1, the second function is -(-x+1) +1.. this equals x-1+1, which is also equal to x.</p>
<p>Mondo, you are almost correct- You forgot your parenthesis. </p>
<h1>x = -x+1</h1>
<p>Thus #(#x) is equivalent to F(f(x)) </p>
<p>Plug in the equation.</p>
<p>-(-x+1) +1 </p>
<p>Distribute negative and we get (x-1)+1 = X</p>
<p>If you need help on the other two questions, then post them.</p>
<p>i cant post graphes on here.</p>
<p>Note: if you have problems, please post in my thread. I'd be happy to help you there. But make sure to be able to type out the problems completely or give me a link/page reference in the blue book.</p>