<p>I remember that I had understood how to do this problem once when I reviewed the error, but I forgot. So if something can re-explain this to me, it would be gladly helpful and appreciated.</p>
<p>The</a> Official SAT Question of the Day</p>
<p>First, what I did was plug in 4 for length and 2 for width. Now can anybody tell me how to go from there?</p>
<p>Damn dude, did you see collegeboard’s explanation? It’s ****ed up…</p>
<p>Okay, so if you wanna go with length= 4 and width= 2:</p>
<p>**Initial area **of rectangle= 4*2 = 8</p>
<p>
**So, **length = 4 + (20% of 4)
Or, length = 4 + 0.8 = 4.8</p>
<p>
So, width = 2 + (30% of 2)
Or, width = 2 + 0.6 = 2.6</p>
<p>New area of rectangle= 2.6*4.8 = 12.48</p>
<p>Increase in area of the rectangle= new area of rectangle - initial area of rectangle
= 12.48 - 8
= 4.48</p>
<p>**Now **you have the increase in area in terms of units.</p>
<p>
</p>
<p>100% * (increase in area in terms of units / initial area of rectangle)
= 100% * (4.48 / 8)
= 56%</p>
<p>It would have been easier to calculate if I had taken L=1 and B=2…</p>
<p>I should correct myself. I just looked at CB’s solution again and realized it is way simpler and faster… But I prefer working with constants.</p>
<p>Just plug in 100 for the length and wide, and it should be easy for you from there. So the area of the original is 10,000 and the increased area is 15,600, thus plugging into the percentage you will see that answer C is correct.</p>
<p>Yeah, thanks so much for refreshing my memory. I’ve ran into this question couple of times, but I needed another review to see where I was doing wrong.</p>
<p>Haha guys I picked 56 randomly and got it right. lol</p>
<p>Lol, I picked 1 for both length and width.</p>
<p>1.2<em>1.3 = 1.56
1</em>1 = 1</p>
<p>(1.56-1)/1*100% (simple percent increase formula) = 56% area increase.</p>