<p>Equation for a circle centered at (0,0) is x^2+y^2=r^2 where r is the radius.</p>
<p>i love the distance formula, it really isnt hard at all.</p>
<p>The distance formula:</p>
<p>Let 'x' be the absolute value of the difference between the two x coordinates. Let 'y' be the absolute value of the difference between the two y coordinates. The distance formula is simply the square root of x^2 + y^2, and is indeed a derivation of the Pythagorean theorem, where distance is denoted by 'c' (a^2 + b^2 = c^2)</p>
<p>In order to find out if the points are within the circle, their distance from the center (0,0) has to be less than the length of the radius. </p>
<p>Thus, for an example point (A,B), an example of an inequality could be:</p>
<p>(A - 0) ^ 2 + (B - 0) ^ 2 <= 10 (length of radius), which is essentially the circle formula.</p>
<p>Hope this alleviates some of the confusion.</p>
<p>Fundamenthal Thoerem of Calculus [Parts 1 and 2] owns.</p>
<p>"(A - 0) ^ 2 + (B - 0) ^ 2 <= 10 (length of radius), which is essentially the circle formula."</p>
<p>That's wrong. The right side is 100, not 10, so the final, definitive answer is:</p>
<p>x^2+y^2<=100 is on and in the circle.</p>
<p>i think x^2 + y^2 = 100 is the easiest equation to use. Its just plugging in points.</p>
<p>if it's less then it's inside the circle.<br>
if it's greater then it's outside the circle.</p>
<p>Ah, did I put 10? Sorry, meant 100... pardon me.</p>
<p>Thanks you guys, I got 35/37 on the assignment! :)</p>
<p>Never mind</p>