<p><a href="http://i.imgur.com/V8hoc.png%5B/url%5D">http://i.imgur.com/V8hoc.png</a></p>
<p>I dunno how to do it!</p>
<p>Correct answer is C.</p>
<p>Help please.</p>
<p>Thanks :D</p>
<p><a href="http://i.imgur.com/V8hoc.png%5B/url%5D">http://i.imgur.com/V8hoc.png</a></p>
<p>I dunno how to do it!</p>
<p>Correct answer is C.</p>
<p>Help please.</p>
<p>Thanks :D</p>
<p>Visualize a right circular cylinder. If you don’t know what one looks like, Google it. The height of the cylinder is 5; the radius is 2. These two line segments (5 and 2) form a 90 degree angle (again, visualize it), and thus forms a right triangle whose hypotenuse is sqrt(5^2+2^2) = sqrt(29). The hypotenuse goes from the end of the radius (the center of the base) to the circumference, so its length is the distance that the question is asking for, sqrt(29). So C, sqrt(29), is the answer.</p>
<p>This should be easily solved with the Pythagorean theorem. </p>
<p>If you draw a simple figure, you can see that the distance from the center of one base to any point on the CIRCUMFERENCE (just the circular line, not any point on the base) of the other base exactly equals the side of the hypotenuse of a right triangle with two other sides of 2 (= RADIUS of base circles) and 5 (= height of cylinder) in length, which translates to: rt(5^2 + 2^2) = rt 29</p>
<p>Hope that helps</p>
<p>I feel dumb now, especially since this is the only one I missed in this section!</p>
<p>Thanks.</p>