<p>how would u get the volume of this?</p>
<p>y=x, y=0, y=4, x=6 and it revolves around x=6</p>
<p>and </p>
<p>y=1/x, y=0, x=1, x=4 and it revolves around y=4</p>
<p>THANKS</p>
<p>help plxzzzzzzzzzzzzzzzzzz</p>
<p>please guys</p>
<p>ohay. you can several functions. find the points that they interesect. set up the integral accordingly with the function on top in relation to y. </p>
<p>have that bound x = 6, and then revolve that to a solid. you can use the shell method here to help express that with 2pi integral from (value to value) that the proper functions accordingly squared with the whole pirsquared thing. </p>
<p>hope that helped! ( iened to practice too for the test)</p>
<p>For the first one, you could use shell method of the 2pi the integral of (6-x)(which is the radius) times (x)(the height) dx from x=0 to 4 so it’s 2pi Integral of (6x-x^2)dx from 0 to 4 which comes out to be 160pi/3 which is approximately 167.552.</p>
<p>The second one, you would do disk/washer method of pi Integral of ((4)^2 - (4-1/x)^2) dx because the 4 is your outer radius and (4-1/x) is your inner radius, bounded from 1 to 4, which should get you approximately 32.48</p>