Impossible Math Problem-CAN'T BE DONE!!!

<p>The entire math department can't come up with the correct solution to this BC Calc question.</p>

<p>Let f be the function given by f(x)= e^(-2x^2) (read as e raised to the negative 2 x squared)</p>

<p>(a) Find the first four nonzero terms and the general term of the power seriews for f(x) about x=0.</p>

<p>(b) Find the interval of convergence of the power seriews for f(x) about x = 0. Show the analysis that leads to your conclusion.</p>

<p>(c) Let g be the function given by the sum of the first four nonzero terms of the power seriews for f(x) about x=0. Show that l f(x) - g(x) l < 0.02 for -0.6 less than or equal to x less than or equal to 0.6.</p>

<p>general term (-1)^n*(x^(2n))/(n!)</p>

<p>converges for all x</p>

<p>i would do c but im lazy, then again im too lazy to give first four terms</p>

<p>Yeah, for the first one just do e^x then insert -2x^2 for x. For two, do the ratio test. For the last one, this is just a glorified alternating series remainder problem. Take the 5th term of the series then use it to see that the error is less than .2 (because l f(x) - g(x) l is actually the expression for error)</p>

<p>yea forgot to type the 2
(-1)^n*(2^n)((x^(2n))/(n!)</p>

<p>Can we stop with the idiotic titles like "impossible" and "math geniuses only?" If its a BC calc problem, be assured its doable and not very difficult.</p>

<p>good point but i think dramatic titles are becoming a staple of this forum ie banned for life thread, good or bad depends on the individual</p>

<p>lol tetrahedron wins</p>

<p>did some type of race take place or something I dont exactly recall anytype of competition taking place, i would of brought my running shoes if so</p>

<p>lol vecter wins</p>

<p>(not all competitions are athletic, but if running shoes help you with math, so be it)</p>