<p>Uh... if you just wanted the basic formula,
integral (ln ax)^n dx = x [(ln ax)^n] - n [integral (ln ax)^(n-1) dx]
n = -1</p>
<p>Which, of course, doesn't do anything for non-18 people, but :shrug: It's the closest I can get without going into the stuff the other websites have discussed.</p>