<p>I did it in maple and got -Ei(1,-ln(x)), brief inspection indicated that this was the same as Li(x) + C | C = i*pi, where i^2 = -1.</p>
<p>I did it in maple and got -Ei(1,-ln(x)), brief inspection indicated that this was the same as Li(x) + C | C = i*pi, where i^2 = -1.</p>