<p>There is a trick that works with integral e^(x^2) dx from 0 to infinity where you square the integral and convert to polar coordinates. The value you get is rt(pi)/2 I think.</p>
<p>There is a trick that works with integral e^(x^2) dx from 0 to infinity where you square the integral and convert to polar coordinates. The value you get is rt(pi)/2 I think.</p>