January 2009 SAT Math Discussion

<p>oo **** it was perpendicular.</p>

<p>I did exactly what velleity did. no calculus neccesary here haha</p>

<p>can anybody explain the digit question? thanks</p>

<p>what exactly was the digit question asking?i think i got 8 but forgot what it was asking</p>

<p>the digit question was like 1/k gives you a decimal with .1?3???
0< 1/k < 1 and then you had to find the tenths digit of (k-1)/k</p>

<p>the tenth place was 1, the hundredths place was 3. then they asked you what the tenths place was in the decimal representation of k-1/k.</p>

<p>no the answer was 8 ^</p>

<p>okay, thanks</p>

<p>im leaving cc until sat scores come out because this thread is just making me feel worse about sat math section</p>

<p>i still stand by my 5/4 for the slope tangent… i just graphed both 5/4 and 4/3 on my calculator and only the 5/4 works (both circle and line intersect at (-4,3)</p>

<p>and can someone PLEASE explain the one where the answer was between 5 and 6??! or something</p>

<p>ny0rker its 4/3 - the only reason urs is probably intersecting is probably because you tweaked the y intercept.</p>

<p>nyorker: it was def 140. the radius was 3, area of circle was 9pi, so since the area of the sector was pi, the angle of the sector was 40. the question wanted you to find the supplement of 40 iirc so 180-40=140.</p>

<p>how do u get the angle to be 40 from the area being pi?!?!?!?!?!</p>

<p>For the quadrants I put I, II, IV</p>

<p>for the slope one i got 3/2??? i was having a tough time with that one but then i noticed that it didn’t say that it wasn’t drawn to scale so i used the side of the paper and marked the length from (-4,0) to (-4,3) and (i thought) the y intercept of the line was exactly (0,9) so then i used (0,9) and (-4,3) to get the slope and got 3/2</p>

<p>because pi is 1/9 of 9 pi (the area. 1/9 of 360 is 40.</p>

<p>the total area is 9pi, the sector is pi which is 1/9
divide 360 by 9 and u get 40 degrees for the sector</p>

<p>there was one with a picture of a function: that two points of a parabola had a Y value of 6-- and then what the distance between each was?</p>

<p>because the radius of the circle was 3, so A=pi r^2 and so A = 9pi, and then the area was 1/9 of the entire circle.</p>

<p>distance was 2sqrt6 or something</p>