<p>Let's get started. Post math questions here...</p>
<p>Well I thought it was extremely easy. Can’t remember anything I had trouble with :/</p>
<p>Math was really easy</p>
<p>Emabargo is not lifted. We need to wait. The exam was easy</p>
<p>yes, the embargo WAS lifted …look at the sticky at the top. we can discuss now.</p>
<p>Easy (10char)</p>
<p>60 degrees for triangle inscribed within the cube?
90 degrees for triangle with angles in ratios?</p>
<p>wat was the one with the triangle, fine the minimum perimiter or something?</p>
<p>eg 2333 you mean the 3:4:5? i had 75 since it would have been, 45:60:75</p>
<p>3x + 4x + 5x = 180
12x = 180
x = 15</p>
<p>it was 42, but I put 40 (so mad)</p>
<p>^^^^ whats the triangle with angles in ratio question???</p>
<p>Which section was the experimental section, or the one that didn’t count.</p>
<p>I have posted what I think is the solution above.</p>
<p>42?, i put 41. wow i failed</p>
<p>what was the one asking for the area of the quadrilateral with all of the triangles in it</p>
<p>8 students in both clubs? or something along those lines?</p>
<p>8 students in both clubs, 60 degrees for the triangle angle inscribed in a cube, 75 degrees for the 3:4:5 triangle, 42 for the minimum perimeter of the isosceles triangle.</p>
<p>giants22, i put 135 for the area of the quadrilateral.</p>
<p>was the expression P=4y/9?</p>
<p>I had 113 i think</p>