<p>For the parabola opening up, I said a > 0. For which equals 1, I think it was I and III.</p>
<p>The answer for the bacteria was like 13781 or something like that. Answer choice E.</p>
<p>^ I and III agreed. Also a > 0</p>
<p>bear:
I think xquicksilverx is right: III works, too: sq rt (sin^2 (2x) + cos ^(2x)) =1.</p>
<p>Average for remaining scores…I think I got something like 21.6.
And the trig, I put sin(2x)csc(2x) and sqrt of sin(x^2) + cos(x^2).</p>
<p>Oh yeah 21.6</p>
<p>For the limit question, I got 5</p>
<p>I thought it was just sqrt of sin(x^2) + cos(x^2)?..</p>
<p>Sin(2x)Cos(2x) definitely doesn’t ALWAYS equal 1…</p>
<p>I thought sin(2x)csc(2x) worked because sin and csc are reciprocals of each otherrr.
And same, limit question is 5.</p>
<p>Hiking:
Wasn’t it to infinity for the limit? Or was that another problem?</p>
<p>Somewhere
Yes, sin(2x)cos(2x) was false, but since sin and csc are reciprocals, sin (2x) csc (2x) is true (ie always 1).</p>
<p>Somewhere, whooops. I made a typo XD. Sorry for the confusion!</p>
<p>bear
Lim was approaching 2</p>
<p>I got 21.6 for averages and 5 for the limit. I don’t remember infinity as a limit in another question?</p>
<p>And oh shoot, can anyone confirm what choice III was for the trig question? I thought it was sqrt(sin^2(x) + cos^2(x))…</p>
<p>Yes, but why is the answer 5?</p>
<p>There was one with a table and you needed f(f(x)) to be 6</p>
<p>What you think for choice III is right.
I made a typo in my previous post saying that sin(2x)cos(2x) was a right answer (choice I) but I meant to type sin(2x)csc(2x).</p>
<p>When you factor the numerator, you can cancel out the x-2 and you end up with x+3, so you plug in 2 and get 5.</p>
<p>bear
lim (x^2+x-6)/(x-2) = lim (x+3) = 2+3 = 5</p>
<p>Omgg stupid mee. Why didnt i factor???</p>