July 14 CB question of the day

Test Preparation SAT Preparation
1

<p>Four distinct lines lie in a plane, and exactly two of them are parallel. Which of the following could be the number of points where at least two of the lines intersect?</p>

<li>Three</li>
<li>Four</li>
<li><p>Five</p></li>
<li><p>I only</p></li>
<li><p>III only</p></li>
<li><p>I and II only</p></li>
<li><p>I and III only</p></li>
<li><p>I, II, and III</p></li>
</ol>

<p>what the hell? you could make 4 intersections with those lines! Why does CB say its not possible?! Can somebody please explain this to me?</p>

<p>The answers 4 btw. 3 and 5 intersections.</p>

2

<p>I agree. This question is not only worded obscurely, but makes no sense. Can someone please explain this???</p>

3

<p>ok, there are 2 parallel lines. and 2 intersecting lines, hence we have our first intersection. Remember.. these 2 intersecting lines stretch out... this is a plane. So they both stretch out to eventually hit one of the other lines........ there you go.. 2 more intersections....... then there is a parallel line to the line that just got hit....... so 2 more intersections.. so i see 5.. i put 2) 3 III only .. but idk how they got 3 intersections.</p>

4

<p>A hint: pick a point on a "non-parallel" line's segment between the parallel lines and rotate that line around the point.</p>

5

<p>4 total intersection is only possible if the two lines don't intersect. The question says it has to intersect. It's a tricky question, that's why it's rated hard.</p>

6

<p>I had a hard time with this question too thanks for the post I get it now.</p>