June 1 2013 Math Thread

<p>cant be I you would get imaginary roots and any square root is always equal to abs val of that number, im still confused on the triangle one where it gave xyz as variables and z=3x or something and the two angles they gave were 70 and 80</p>

<p>For the Angie time question with the train, wasn’t it more than 30? I mean if his watch said 2:30 (example) and the watch is 7 minutes ahead, isn’t the time 2:23 actually?</p>

<p>@upsilon it said COULD be possible as in one case proves it</p>

<p>@RushBagot for the last time it wouldn’t give an imaginary root but the second part of what you said with the absolute value may be right, I hate this question. I don’t remember your question tho sorry</p>

<p>Tell me the problem again. Then tell me your one case where its possible.</p>

<p>a+b/2 = sqrt(ab) and the case is when a and b both equal -2. Comes out the -2=sqrt(4). The only question is if -2 is acceptable as a sqrt of 4 or not, I assumed it was when I chose my answer but now I’m not 100% sure anymore.</p>

<p>the thing is it is acceptable though it does equal positive 2 because again any square root is always abs val</p>

<p>Can we talk about the angle question again? The one with 3 lines. I’m pretty sure the Q was “If there are 3 lines that all intersect at 1 point, how many angles can add up to more than 90 but less than 180 degrees?”</p>

<p>???,</p>

<p>@ Hittce - √4 does NOT equal -2. The √ ̅ sign implies that you ONLY take the positive square root.</p>

<p>Super starla… only 3 can be great than 90</p>

<p>What the question asking for the n digits… </p>

<p>The 10011002…1020…???</p>

<p>no 4. It didn’t say they had to be adjacent so 2 angles across from each other could each be 100 and then the other 4 could each be 40. 40*4=160 which is b/w 90 and 180.</p>

<p>ak indian it was 122</p>

<p>Did it ask “what is the max number of angles that can ADD up between 90 and 180?” or “what is the max number of angles that can BE between 90 and 180?”</p>

<p>Lol you are both wrong, the angle question was two. It asked for how many possible angles could be greater that 90, implying that they are all 91 degrees then.</p>

<p>@divisionbyzero i agree with you that @hittce’s math is wrong thoughwhen you have any value for x say 2 or -2, square those and you get a positive 4 take the square root of the 4 and you should get ABS VALUE of 2 and then determine that it was not possible because positive 2 usually the abs value of a square root is used when checking for the roots of a quadratic or higher degree function</p>

<p>I’m pretty sure it asked what is the max # that could add to greater than 90 and less than 180.</p>

<p>@DivisionByZero I believe it said “how many angles can be >90 and <180” or something along those lines.</p>

<p>Also, a square root pretty much always implies a positive value. That’s why the graph of sqrt(x) does not go below the x-axis (y is never negative). So I believe the correct should have been II and III only.</p>

<p>@ Extractum11 - If that’s the case and three lines were intersecting at one point, then 3 angles can be between 90 and 180 degrees. Three angles can be 91 degrees and the rest would add up to 87.</p>

<p>No because the angle across from an angle will be equal. With that Q it has to be even.
I still can’t figure out my experimental. Ughhh</p>