June 2006 - Math Level 2

<p>Talk about the test here....</p>

<p>question: wat does 42 correct and 8omit amount to??? any hope for 800? Also, is it bad to retake an SATII. Will an 800 in 1 taking be looked as that much better than an 800 in 2 sittings?</p>

<p>That was so freakin hard...I'll be happy if I broke the 700s...I think I broke 650 though. :(</p>

<p>i thought it was pretty easy, but i was soooo short on time....i probably relied on my calc too much...</p>

<p>42 would be around a 780-800 depending on how they curve it.</p>

<p>Well... I thought it was very easy, however, I ran out of time and had to omit 7 questions. I guess preparing with Barrons makes the actual SAT seem a lot easier. Wut about specific questions guys? Anyone rember a questions wit Log2 bla bla? I think something like find die point (k, 6). And we had to find k?</p>

<p>Yeah...I remember that...What was the answer?</p>

<p>I remember the (1, 5, 10, 100)...50%</p>

<p>I remember the log 2 question. I plugged it into my calc and got 4, but that wasn't even one of the answers</p>

<p>ye i got 50% for the set of (1,5,10,100) as well</p>

<p>i forgot wat the log2 question was..</p>

<p>log2/log(2x^2+6)=6</p>

<p>or something like that</p>

<p>yea... it was weird, i plucked all the answer choices in my calc, but didnet get the exact answer... closest i got was about 1 less than 6, which was weird, dont really kno how to do that one...
that (1,5,10,100) was 50%... because there r 3 possibilities to get a number greater than 100: 1+100,5+100,10+100, and six in total</p>

<p>o ye</p>

<p>just change it to 2^6=2x^2 + 6, then solve from there</p>

<p>AIM Chat: sat2math2c</p>

<p>its</p>

<p>(3/4)(2/3) = (6/12) = .5</p>

<p>how do you join chat rooms?</p>

<p>i think the log questions was a little different... come to the chat guys</p>

<p>right click on your username...send chat invitation...and enter sat2math2c as the room name</p>

<p>"AIM Chat: sat2math2c"</p>

<p>No one's in here</p>

<p>does anyone remember the one where you have f(x) and g(x) and they intersect. you had to find out what points you need to know the intersection. I) all x II) all y III) zeros of f-g</p>

<p>I put I and III. I thought it was okay. Guessed a few, and the rest which I had no idea on, I just subbed the answers into the equations. Barron's make things fun and enjoyable. =)</p>

<p>Yeah, for the finding answers graphically question, I put I and III also. I was definitely an answer, and II I was like.. you could find out the x, but it doesn't actually GIVE you the solutions.. so I put III.</p>