<p>haha, I figured that thread would be deleted. Okay, so until the embargo is lifted lets try to keep thread away from SPECIFIC questions.</p>
<p>Does this post still qualify for the current embargo?: <a href="http://talk.collegeconfidential.com/sat-subject-tests-preparation/426046-embargo-lifted.html%5B/url%5D">http://talk.collegeconfidential.com/sat-subject-tests-preparation/426046-embargo-lifted.html</a></p>
<p>so...we can discuss now? lol just want to make sure</p>
<p>yeah i think so.</p>
<p>that's from december 2007....lol</p>
<p>It was easier than Barron's but I still couldnt finish >.<
Skipped 4 in total
What do you guys think the curve is going to be like?</p>
<p>what was the probability question with the odd sums? I just realized i might have made a stupid mistake.</p>
<p>I think I guessed or omitted that one. Either way at the last minute I did or would of I put 1/4. That's probably the stupid mistake you were talking about. now does anyone have a definite answer?
Plus about 50 I got 2log(cos(x)) but before some people were saying it was 2log(sin(x)). Can someone definitively explain and tell me which one is right?</p>
<p>I think it is 1/2. An odd sum is an even # plus an odd #; if you do odd from group one plus even from group two, you get 1/4. If you do even from group one plus odd from group two, you get 1/4. Total, it's 1/2.</p>
<p>I just realized I made a mistake too...I put just 1/4.</p>
<p>yeah i thought it was too easy. Hopefully I omitted that one. Anyone know the vector one? Was it the one in the third quadrant?</p>
<p>The probability one asked you about the product, not the sum, right?</p>
<p>I'm pretty sure it was the one in the fourth quadrant.</p>
<p>yeah its the fourth quadrant. i don't know what i was thinking Ugh!
Anyways anyone know about #50?</p>
<p>the vector one if it was b-a would have been quadrant 4... i personally read a-b thats why i put quadrant 2.</p>
<p>It asked for the product of odd and even integers thats why it is 1/4</p>
<h1>50 was certainly 2 log cos x</h1>
<p>I got it in the 4th quadrant as well. If anyone wants to discuss this more descriptively, add me to aim: darthloaded</p>
<p>(I'm not sure we're allowed to discuss the test like this in public)</p>
<p>im pretty sure its in the 4th quad too. x was greater in B than A, so the x value has to still be positive. the y was less in B then A, so the y must be negative. pos x and neg y exist only in quad 4.</p>
<p>yeah, i agree w/ the probability, because to have an odd product you must have two odd factors
thus, 3<em>3
so half of 1-10 are odd and half of 1-20 are odd, thus .5</em>.5=1/4</p>
<p>yeah my stupid mistake was forgetting it was 1-20 for the second one, i treated it like 10-20. so i got 1/2 =/
if i did it the above way it wouldnt have mattered though. I found total number of outcomes (100 in my case by counting 10 and 10, not 10 and 20) so it was 50/100. screwed me up.</p>
<p>hopefully thats my only one...</p>
<p>lol i think i might have made a careless mistake for the average one with the bar graphs, can anyone tell me what they put and what theother answer choices were,thanks!</p>
<p>think it was A. But usually mess up on these average problems.</p>