After the exam, if i remember, i will be more than happy to post mine. Be patient though…my exam ends an hour after everyone else’s for some reason (3:50)
we can all work together and give each other answers
I don’t understand why question 13 of the June exam is choice 4
Parallelogram has to be 1 pair of opposite sides BOTH parallel and congruent. Not one set parallel and the other set congruent.
Guys bless this discussion with the multiple choice answers and how to do the part 2 and part 3 questions.
@hava939 thanks
Question 24 of the January exam Is confusing too …
Here are my MC answers:-
3 4 2 1 3 4 3 4 1 2 4 1 2
4 4 3 1 2 1 1 2 3 4 3
What did u guys get fr the last question
Very confusing
Here are my answers:
1-3
2-4
3-2
4-1
5-3
6-4
7-3
8-4
9-1
10-2
11-4
12-1
13-2
14-4
15-4
16-3
17-1
18-2
19-2
20-1
21-2
22-3
23-1
24-3
25- Translate triangle ABC 6 units down and 6 units to the right, then reflect the translated image over the line y=-3.
26- P (12,2)
27- The two triangles are similar because of SAS for similar triangles, so their corresponding angles are congruent. Since if two lines, cut by a transversal, have congruent corresponding angles, the two lines are parallel, AB is parallel to CD.
28- R=17 because conjunctions add up to 90.
29- Yes because radian measure = (arc length)/(radius), (13pi/8)/(6.5)=(pi)/(4) since if two fractions are congruent, the product of the means equals the product if the extremes. This gives 6.5pi = 6.5pi, which is true so Dominic is correct.
30- arctan (10/4) = 68 degrees.
31- Extend the radius and then mark off the length of teh radius so that the point on the circle is the midpoint, then find the perpendicular bisector.
32- 57.7 gallons.
33- The two pairs of alternate interior angles are congruent since the opposite sides of a parallelogram are parallel. Thus, they are similar by AA for similar triangles.
34- The transformation is a dilation about the origin by a scale factor of 5/2. They are similar because they can be mapped onto each other by similarity transformations (dilation).
35- It is a parallelogram because the diagonals bisector ach other. It is a rhombus because the diagonal bisects an angle. It is an isosceles triangle because every side of a rhombus is congruent. It is a right triangle because the diagonals of a rhombus are perpendicular.
36- They must be parallel because we have to use the ratios of the similar triangles to find the height. For two triangles to be sinilar, their corresponding angles must be congruent. Since if two lines, cut by a transversal have congruent corresponding angles, they are parallel, the two diameters are parallel. The height is 15 inches. The volume is 24.9 cubic inches.
How is the height 15 inches I got 7.5
Here are my multiple choice:
1- 3
2- 4
3- 2
4- 1
5- 3
6- 4
7- 3
8- 4
9- 1
10- 2
11- 4
12- 1
13- 3
14- 4
15- 4
16- 3
17- 1
18- 2
19- 2
20- 2
21- 2
22- 3
23- 1
24- 3
I got the same as @kimclan1 for most of the rest… I got the circle radians one wrong, and the volume wrong (idk, dumb mistake. Overall i found this much harder than the practice.
You have the proportion (1.5)/(x+5) = (1)/(x). That is 1.5 = x+5, so .5x=5. Multiply both sides by 2 to get x=10. Howver, you have to add 5 onto x because it wants the big cones height, so the answer is 15 inches.
Same it was hard
I thought that it was hard to explain the first part of the last question.
What was question 23? The actual question
If it was the one with the similar triangles consisting of two transversals, it was 10 I think.
No I don’t think it was that
Explaining some of those was super hard! I used some bs with the side splitter theorem for one of them lol
And for the Domonic question I used the radians formula 2arc= r Thera
Got the same answer tho