<p>hey! even though its much easier than IIc, its still an sat2 right :D. Anyhoo, discuss away! =D</p>
<p>I thought it was alright! I think I only omitted 3 and that was just because I ran out of time. (I have a habit of being horribly slow on standardized math tests.)</p>
<p>Does anyone know what they got for the token one? I kind of RUSHED through it just as my proctor was calling time and put down 3n/7, I believe.</p>
<p>was that the quesiton w/ the ratio?</p>
<p>Yeah the coin ratio thing was answer A.</p>
<p>Oops,
alright - so what was that Elena..Kristie..and the school one?
Did it involve subtracting the given sides + .62 = "x" ?
and then adding the given sides + .62 = "y" ?
and then x < d < y ?</p>
<p>I ran out of time after I did question 45 and put down rough guesses for the rest :(</p>
<p>I was very confident in the 45 that I took my time to answer, so I'm trying to decide whether I should cancel or not.</p>
<p>I omitted one, and I JUST ran out of time on the last one. 30 more seconds, and I would have had it. Oh, for the last one, you drew a school, and then two circles to show the radius. The minimum would be the distance to the school, then back to the other girl's house (.90) and the maximum would have been the trip to the house and back added to the distance to the other house (1.52). At least, I think so.</p>
<p>Noo, it was .96 is less than x is less than 1.52.</p>
<p>It's .96 because the shortest route possible was from school to her friend's house (which was .62 miles away) and from that house to her own house (which was .28 miles from the school). Now, if both her house and her friend's house were on the same basic line, she'd travel .62 miles to her friend's house from school and then back .34 miles on the same line to her house. Making it .96 miles total.</p>
<p>Think of it this way....</p>
<p>Friend's house---------------her house------------------school
(friend's house and her house are .34 miles apart. Her house and school are .28 miles apart.)</p>
<p>Oh... you're right... Good thing I ran out of time, then.</p>
<p>I SO underestimated this test. I'd cancel it, but I think I got 750+ for US History. I'll retake it or Math 2 in November.</p>
<p>Do you remember the choice letter for the house one?</p>
<p>And what was this question:
if i is -1, and a is a positive number, what is equivalent to i^a?
1. i^a+1
2. i^a+2
3. i^a+4
4. i^2a</p>
<p>The above choice numbers are out of order, I think.</p>
<p>That one is i^a+4 because i^4 = 1, and any number multiplied by 1 is equal to itself. You can plug in some numbers if you want:</p>
<p>i^1 = i
i^5 = i^4 * i^1 = i^1 = i</p>
<p>i^2 = -1
i^6 = i^4 * i^2 = i^2 = -1</p>
<p>what about the one w/ two plates seperated by 4 inches and a circle center equidistant w/ raidus 1 inch or s/thing. The answer was none right?</p>
<p>That's what I put.</p>
<p>Darn, I definitely underestimated it as well.
I took it in the spur of the moment but I'm really not sure how I did. </p>
<p>First half of the test was a lot easier than the last half, for me.</p>
<p>Umm...the questions are supposed to get progressively harder, for every subject test I believe. </p>
<p>Anyways, another explanation of the i^a question...</p>
<p>There is a pattern that repeats itself every four whole values of a.</p>
<p>i^1 = i
i^2 = -1
i^3 = -i
i^4 = 1
i^5 = i
i^6 = -1
etc etc...</p>
<p>So i^a = i^(a+4)</p>
<p>You could have just set your calculator mode to a+bi mode (allows imaginary numbers) and tested each answer choice by plugging numbers in. </p>
<p>~~~~~~~
I also put none for the two planes thing.</p>
<p>Does anyone know what the answer was for the one with the two triangles inside the circle, and one of the options was "The answer cannot be determined from the given information" or something like that? (Sorry I can't remember more specifics about the problem).</p>
<p>Overall, I thought the test was pretty easy. #49 (compounded interest) was the only one I had to randomly guess on because I couldn't remember the formula, but apparently my friend got the same answer I did, so hopefully it was right!</p>
<p>I put "The answer cannot be determined..." as the answer for the triangle one.</p>
<p>I got an answer for that question about the two triangles inscribed in the circle, with the diameter of the circle as one of the sides for both of the triangles (meaning that I did not get "the answer cannot be determined"). I can't remember the question that clearly, and/or how I solved it, but I think if you used the fact that they are right angles, you were able to get the answer. All I remember is that I used this rule in order to determine my answer.
See more info on this here:
<a href="http://www.learner.org/channel/courses/teachingmath/grades9_12/session_04/section_01_b.html%5B/url%5D">http://www.learner.org/channel/courses/teachingmath/grades9_12/session_04/section_01_b.html</a></p>
<p>Also, what did you guys get for the question with the three options, I, II, and III, and you had to choose which of the three were true statements. It involved something with p being a prime number, and n and m being two odd or consecutive numbers. I can't exactly remember. I believe that option II was that if you square p (the prime number) it will always have three divisors, which I thought was incorrect. The answer I chose was that "I and III" were both correct. What did you get?</p>
<p>Oh... I think that's the first/only question that I got wrong.
I think I just noticed...
p^2 would be only divisible by three things: p, 1, and p^2.
Oops... correct me if I'm wrong.</p>