<p>In a group of 10 people, 60 percent have brown eyes. Two people are to be selected from the group. What is the probability that neither person selected will have brown eyes?</p>
<p>Please help me understand the answer to this question. TIA.</p>
<p><<this is="" from="" college="" board="" sample="" test="" question="">></this></p>
<p>is the answer 2/15?
or 13%?</p>
<p>Yes, how do you get that?</p>
<p>ok so first of all you know that 4 ppl do NOT have brown eyes.</p>
<p>what you're trying to find is (prob of choosing brown eyes)/(prob of choosing 2 random ppl)</p>
<ol>
<li><p>prob of NOT choosing brown eyes: 4 nCr 2 since 4 do NOT have brown eyes.</p></li>
<li><p>prob of choosing 2 random ppl: 10 nCr 2</p></li>
<li><p>solve the equation on your cal: (4 nCr 2) / (10 nCr 2) = .1333....</p></li>
</ol>
<p>So 6 people have brown eyes, 4 people do not. 4/10*3/9= answer
(4 people w/o brown eyes/10 people)(3 people w/o brown eyes/9 people)</p>
<p>I knew it was easy! Thanks inteli people!! Good luck for tomorrow :)</p>
<p>ah. tomorrow after test = freedom!</p>
<p>it's even simpler than that. (4/10)(3/9)=(2/5)(1/3)=2/15</p>
<p>Oh, someone already said it. My bad.</p>