<p>95% confidence interval means that 95 out of 100 values will be contained in (insert range here)....and that we are 95% confident that the true mean/proportion of (insert problem context here) lies between (insert rang)</p>
<p>normal is used only when you have z scores it is normcdf(z,99) <you never really need to use pdf</p>
<p>geometric is when you want the probability of only ONE sucess. Geopdf is for on specifically the nth trial geopdf(P sucess, nth trial) if you want a sucess WITHIN n trials (ie n or less) then use cdf Geocdf(P sucess, nth trial)</p>
<p>Binomial is P of x sucesses within n trials again pdf gives exactly and cdf is within. key order is binomialpdf/cdf(n,P,x)</p>
<p>just a quick ?
when a prob asks you to find an sample size with 95% confidence so that the margin of error is 5...
m = z* x sigma/square root of n...</p>
<p>does m = 5 or 2.5 (2.5 on each side makes the total 5)?</p>
<p>as far as CI's
I suggest not using the phrase "lies between"
instead, use captures or contains</p>
<p>only because the former suggest that the true parameter is moving within the range when actually it is the rang that is moving to "capture" the true parameter</p>
<p>wait .. but if the problem asks him to find the sample size WHEN the margin of error is 5, isn't margin of error just ... 5? He's trying to find sample size n, not margin of error. Or did I misunderstand it?</p>
<p>Lucidity, whenever they ask you to find n for a certain margin of error, You use that number as m in the equation just like you said. Dpat seemed to interpret margin of error in a different way, and that's why explained it like that in post#27.</p>
<p>I'm a little confused on two thigns. Which Chi test is the one with the matrixes, what's the other one (where you do List 1, list 2, than (O-E)^2/E)?</p>
<p>chi-squared test for independence and chi-squared test for goodness of fit are both done using matrices</p>
<p>Not even sure how to do a test for homogeneity, i think it was #6 for one AP FR</p>
<p>Btw, I see a lot of variations between conditions for CHI-SQUARED.
Supposedly our teacher told us to use the following for all three tests:
1. SRS
2. all expected counts > 0
3. no more than 20% of expected counts < 5</p>
<p>someone verify? i'm pretty sure it doesn't apply to homogeneity but i really need to find a fully worked example of that test anyways.</p>
<p>Goodness of fit is done with two lists. Homogeneity and independence are tested using matrices (they are essentially the same test, just different explanations).</p>
<p>One assumption that I've seen is independently collected samples, not sure if that one is common though.</p>
<p>EDIT: And of course the data should be counted...</p>
<p>Your null hypothesis is typically mu=0 or some variant of that (like mu1-mu2=0 for 2-sample tests). Your alternate hypothesis on the other hand usually has doesn't-equal, greater-than (>), etc.</p>