Level 5 BB math question; hardest one i've ever seen

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1

<p>Hey, this is from BB edition 2 (the newer one), Section 3, question 19.</p>

<p>For those of you who don't have the BB, I'll write the question below (slightly paraphrased, because there is a figure present; also, note that "sqrt" means "square root of"):</p>

<p>"A pyrmaid has altitude h, and square base sides of m. the four edges that meet at the uppermost vertex (the point/tip of the pyramid) also have length m. What is the value of h in terms of m?</p>

<p>a) m/(sqrt 2)</p>

<p>b) (m * (sqrt3))/2</p>

<p>c) m</p>

<p>d) (2m)/(sqrt 3)</p>

<p>e) m * (sqrt 2)</p>

<p>The answer is A.</p>

<p>Thanks for the help!</p>

2

<p>From SilverAurora, I hope this is the same problem.
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3

<p>OHHHHHHHH makes so much sense</p>

<p>thanks!</p>

4

<p>Sorry, I don’t quite understand this. How do you get from the pythagorean theorem equation to the answer?</p>

5

<p>There are 2 variables, h and m, so you solve for h.</p>

6

<p>Weird that this was mentioned, I just got done taking that test. The math sections on that test were the easiest I have ever seen, even though I made 3 careless mistakes!</p>

<p>@Kestrel Just imagine it as a 45-45-right triangle. We already know the side opposite to the right angle is m. Now to find h all you have to do is remember the formula to a 45-45 which is s,s,s sqrt 2. So just divide m by sqrt of 2 to get h.</p>