logrithium probls on act math?

<p>How much of the act math has the emphasis of logrithium in it. I havent covered in my high school math class yet.</p>

<p>4 questions usually, but there are exceptions</p>

<p>what review books cover probs that are like</p>

<p>log squared 23 + log squared 2= log squared X. Something like that. I saw that on that purple pratice test booklet I got from school. I dont get a freeking clue on how to do those problems.</p>

<p>Logs are pretty easy once you learn them. I'll try to explain but I'm not a teacher so maybe someone else could do a better job.</p>

<p>"Log x" means "The exponent of 10 that equals x"</p>

<p>Log 100 = 2
becuase
10^2 = 100</p>

<p>If there is a small number in between "Log" and "x" that is the "base". If there is no small number, the base is automatically ten.</p>

<p>For all real numbers:
(y=a to the x power)=(x=log-base a-y)</p>

<p>i haven't covered logarithms in my precalc class so i just self studied it very easy to learn </p>

<p>heres all you really need to know: Logarithms</a> - Topics in precalculus</p>

<p>btw, its usually one problem per test</p>

<p>I LOVE LOGS.</p>

<p>And yeah, they show up sometimes.</p>

<p>if you've gone through your math department up through precalculus and haven't learned anything about logs, that is a problem. you should probably mention that to them, since they are a) an integral part of math education and b) on the ACT. it's almost irresponsible to not teach it</p>

<p>im in precalc now and i've learned about them for a whole chapter this year and last year.</p>

<p>but anyway, any logs you may encounter on the ACT are usually very basic, nothing too extensive. they usually just require you know some of the basic rules and properties.</p>

<p>I learned about logs in Alg 2 and Analysis. The ACT doesn't really have a ton of questions about it, so don't worry if you don't really get it. If you are really worried about, just reading about it in a review book will probably teach you all you need to know.</p>

<p>log's easy c'mon</p>