<p>which of the following shifts of the graph of y = x^2 would result in the graph of
y = (x^2)-2x+k, where k is a constant greater than 2? </p>
<p>A. left 2 units and up k units
B. left 1 unit and up k+1 units
C. Right 1 unit and up k+1 units
D. Left 1 unit and up k-1 units
E. Right 1 unit and up k-1 units</p>
<p>best way is to assume a k and make the graph of both.
If you do this way, you will notice that, the answer is E.</p>
<p>Theoretical way,
Let k = 3</p>
<p>then, x^2 -2x+3
= x^2 -2x +1 + 2
= (x-1)^2 +2
y-2=(x-1)^2</p>
<p>x-1 imples that the graph is shifted 1 unit right.
y-2 imples that its shifted two units up . ( 2 units = 3-1units = k-1 units)</p>
<p>and the answer will always be this as-:</p>
<ol>
<li>always the only way to form a perfect square of the 2nd equation will be to take 1 out of the assumed k which implies that always k-1 will go to the left hand side.
Thus graph will always shift 1 unit up and k-1 unit to right.</li>
</ol>
<p>Hope i Helped.
PS - i am also taking SAT IIC this dec. Best of Luck !!!</p>
<p>omg the first way is so easy. I don’t know why I didn’t think of that I do it for a lot of questions. </p>
<p>thanks</p>
<p><a href=“SAT SUBJECT TEST. Math Level 2, Test 1, Question 47 - YouTube”>SAT SUBJECT TEST. Math Level 2, Test 1, Question 47 - YouTube;
This guy has all of the explanations</p>