<p>i got 9 for the median question</p>
<p>nope, its 11 for the median question.. how is it c.. i thought the 2 represented height of each pail.. cuz there were 5 pails right in the first one.. so 2 times 5=10+8 equals 18.. same with the one with 3.. 2(height of each pail) times 3=6+8=14..</p>
<p>i dunno, how did you guys get b or c or wutever</p>
<p>Im pretty sure it was 3 for the question of how many x values will give a negative answer.</p>
<p>The problem was (2n + 1)(3n-11). The n values that would make this negative are 1, 2, and 3. If you go to 4 then both values are positive. If you go to 0 then the answer is 0 (not negative) and if you go to negative then both of the values come out negative which makes the whole thing positive.</p>
<p>haha you wanna know how i did that problem? I graphed it in my calc, and had to guess between 3 and 4, but i put 3 i think. i knew there was an easier way..</p>
<p>anyone have the probability question about Maria or something in her class, teacher assigned them desks, 36 kids in the class, 5 rows, 8 kids per row, her probability of being seated in last row?</p>
<p>Solve the parentheses, and you get 6n^2 - 19n - 11. Put it into your graphing calculator. Tell me where it goes negative.</p>
<p>To make things easier, it's at 4 integer values.</p>
<p>No sorry Parian, plugging in 0 is still acceptable because it produces a NONEGATIVE final answer.</p>
<p>The possible values were 0,1,2,and 3 so the answer was 4. 5 of my friends confirmed this answer to me, including a USAMO qualifier, so unless we were all drunk...which is actually quite possible after the wild party last night(jk).;)</p>
<p>Q: If (XY)+(X^2) is odd then which of the following must be true.
A: I and III or X must be odd and (X+Y) must be odd as well.</p>
<p>Ahhhh...I put I and III and then erased it and put only III...soooo stupid!1</p>
<p>My bad i forgot about 0.</p>
<p>i wonder if there were actually like 5 experimental sections, just for april fools day or something, and in reality we only had 5 sections (the easy ones!) that count.</p>
<p>Someone want to explain the median question? If there are 8 1300, 4 1600, x 1500 or something, then adding anymore than 3 would mean the median wouldn't be equal to 1300</p>
<p>does anyone remember the question with the isoceles triangle....... average was like 70..... i had no idea... neone know the answer</p>
<p>Does anyone remember the driving problem. It was like:</p>
<p>You are driving at 20mph for the first 10 miles and then 40mph for another 10 miles. What is your average speed. Please tell me this wasnt a trick question. It was the very last question on the grid in and im like "*** this is too easy to be considered Hard."</p>
<p>yes
if the average of non congruent sides are 70, that means the total is 140, leaving you with 40 deg. for the other angle. but the other angle is one of the congruent ones, so that makes the other congruent ones 40 also, making the noncongruent angle 100 degrees.</p>
<p>hmm.. it was 80/3.. and isoceles triange was 40, 40, 100, so 100 was ur answer</p>
<p>For isoceles i put 100. The sides were 40, 40, 100. 40 and 100 averaged together was 70. I think i got it right?</p>
<p>OK here's the deal with the median one...iff there are 8 1300, 4 1600, x 1500 then the highest odd number X could be to make 1600 still the median is 11. Since there would be a total of 23 and thus the median would be the 12th value which would still be 1200 cuz you're on the last one.</p>
<p>Something like this...</p>
<p>800,800,800,800, 1200,1200,1200,1200,1200,1200,1200,1200(BINGO!!!-12th value), 1500,...,1500</p>
<p>80/3 for the driving one? Please explain.</p>
<p>Wait, the median was 1600, not 1300? Damn.</p>
<p>so the answer for the median one is 11 right?</p>
<p>For that one problem about where kids are going to college, did you all get 12+9+11 for 30 kids who didn't go to College Z but did go to X and Y? this was a venn diagram. For the triangle one I got 100 since 100+40+40=180 and 70 is the average of (100+40)/2</p>