Math CHALLENGE...Post the hardest math SAT I questions you can find..

<p>i could use the practice :)....let's see who can solve it the most efficiently...we can all learn from these efficient methods...</p>

<p>Given a triangle ABC as described below: Side AB = Side AC. Draw a line from C to side AB. call that line CD. Now draw a line from B to side AC. Call that line BE. Let angle EBC = 60 degrees, angle BCD equal 70 degrees, angle ABE equal 20 degrees, and angle DCE equal 10 degrees. Now draw line DE. The question--find what angle EDC is. </p>

<p>(This can be, and is meant to be, solved geometrically, without trig. )</p>

<p>is it 10 degrees? LOL just a guess</p>

<p>No, it is not.</p>

<p>Is this 75?</p>

<p>Is it 60 degrees?</p>

<p>oops i put my tick mark on the wrong side.. giving me the wrong isoceles!! did it again but i still thinkg i got it wrong .. 65? .. if the mid point (let's say O) is where everythign intersects and BOC = 50 thus DOE = 50 .. (my logic might be wrong but i believe triangle DOE is an isoceles) leave 130 degrees divided by 2.. 65? there must be an easier way ahha</p>

<p>EDIT: Vehement answers works out for me.. did that the first time with my wrong isoceles.. but changed my method second time around =/ whoops</p>

<p>double post</p>

<p>its 70.....</p>

<p>ok the full steps</p>

<p>first add up bde, ebc, ecb and ecd. you will get 160.</p>

<p>180 - 160 = angel a</p>

<p>180 - angel a(20)/2 = ade = 80</p>

<p>180 - dbe - dbc - bce = angel bdc = 30</p>

<p>subtract bdc(30) and ade(80) from 180 = the answer = 70</p>

<p>:) ........ :)</p>

<p>It is not 70.</p>

<p>It'll make it so much easier to jump right to the next question if you are not interested in one before.
thanks much!</p>

<p>Hmm you copied the question wrong then? or i seriously misread. i have figured out every angle in the triangle so i really don't know where my prob is</p>

<p>I messed up</p>

<p>Vehement, the problem is far from being a sixty seconds SAT question. It is the Gruber's challenge. It takes a ... long time to develop a solution.</p>

<p>And btw, "180 - angel a(20)/2 = ade = 80" is where you go wrong. You can't assume that.</p>

<p>No the question said DE is // to BC right?</p>

<p>edit: misread</p>

<p>No, it did not. Look at the angles, it would be impossible for DE to be parallel to BC.</p>

<p>And the answer is definitely not 70.</p>

<p>ya you are right...wait a sec</p>

<p>Here's another that is a bit harder than the typical SAT:</p>

<p>How many sets of 10 can be taken if you have 10 identical blue towels and 10 unique red towels?</p>