Math geniusess helpp (AB or BC calc)

<p>how would I go about this question:</p>

<p>Given the sum of an infinite geometric series is 2005. If each term is squared, then the sum of all those terms is ten times the sum of the original geometric series. Find the ratio of the original geometric series.</p>

<p>sum to infinity for the first series equals 2005 , here the first term is A and ratio is r.........you get a equation in terms of A and r</p>

<p>the second series has a first term A^2 and ratio r^2 sum for infinity of this series is equal to 10 times the first thats 2005X10......you get the second equation</p>

<p>r equals to 399/403</p>