<p>I have a question upon 12/475, Blue Book. Are there faster and painless way to deael with?</p>
<p>yep, there is.
(x-y)(x+y) = x^2 - y^2
since x+y = 11, you know that (x-y) shoule equal 7, in order to have x^2 - y^2 =77
now you have two equations & 2 unknown variables.
x-y = 11 and x+y=7
when you add those two, you get 2x = 18
therefore, x=9</p>
<p>Thanks
Can you introduce some concepts of how to solve a remainder problem. I attempt to follow a method of Godot, but it is a bit abstruse and I don't know how to apply to SAT questions.</p>
<p>Let's take this for instance:</p>
<p>When 15 is divided by the positive integer k, the remainder is 3. For how many different values of k is this true?</p>
<p>dividend = divisor X quotient + remainder</p>
<p>But can I apply this into such a question without knowing quotient?</p>
<p>well.. I have no idea how to use such methods..
I use my logic to solve most of the problems.. i dont think i can explain exactly how i do it in words.. but i'll try..</p>
<p>15 / k = a and remainder 3 , you can rewrite this as<br>
a * k = 12 + 3 </p>
<p>now you know k has to be a facter of 12, and bigger than 3 ..
(if it's not a factor of 12 or smaller than 3, you would not get 12)</p>
<p>numbers that are factors of 12 and bigger than 3 are 6, 4, and 12
so the answer to the question is 3..</p>
<p>sorry, that was a horrible explanation :(</p>
<p>No, no thanks a lot. I am checking my concepts. I am really weak in Math and Science.</p>
<p>Perhaps you can help me with this question, it supposes a bit easier I guess, so I can grasp the principle easier.</p>
<p>When the positive integer n is divided by 6, the remainder is 2. What is the remainder when 24n is divided by 36?</p>
<p>so...
Let's apply your logic here: 6 / n = a and remainder</p>
<p>so a * n = 6 + 2</p>
<p>so an = 8</p>
<p>but the I don't know what to do next...</p>
<p>lol, Cuong, me and you are almost twins when it comes to SATs... I posted a thread about these very same questions a few weeks ago, and it seems our essays are similar in their humanities slants :P. Good luck tomorrow! I am also trying to increase my math score!</p>
<p>:)</p>
<p>Help!!!!!!!!!, Can Anyone Help??</p>
<p>Ive been doing maths all night for tomorrow, and Im struggling to hit 670.</p>
<p>Fail. And D-day tomorrow. </p>
<p>:'(</p>
<p>
[quote]
When the positive integer n is divided by 6, the remainder is 2. What is the remainder when 24n is divided by 36?
[/quote]
There's one way of making these problems a bit simpler which has always helped me in dealing with them. Just set n equal to a value that satisfies the information they give you. In this case, that information is that n has a remainder of 2 when divided by 6. So, what could n be? Well, 2 has a remainder of 2 when divided by 6. So, just plug in 2 for n...24n = 24*2 = 48, and 48 divided by 36 has a remainder of 12. The answer, then, will be 12.</p>
<p>These remainder problems, at least for me, become a lot less intimidating when you're just plugging in numbers and working through them like this, instead of trying to deal with weird variables and such.</p>
<p>Can you explain a bit more?? Thanks a lot!</p>
<p>Basically, you just dissect the problem into two parts: the information that tells you what N is and the question asking you to do something with N. You can use the first part to decide a value for N, and then you plug in that value for N in the second part, so you don't have to worry about using variables.</p>
<p>In the example question, the two parts are like this:
Part 1 (information): "When the positive integer n is divided by 6, the remainder is 2."
Part 2 (question): "What is the remainder when 24n is divided by 36?"</p>
<p>Part 1 tells you what n is. There are lots of possible values for n (an infinite number, in fact), like 2, or 8, or 14, or 20, and so on. The idea is that it doesn't matter which one you choose (as long as it fits the information), so you can simply pick one and plug it in to Part 2.</p>
<p>Just try it: we'll first take n = 2. Part 2, then, becomes 24n = 24 * 2 = 48, and 48 divided by 36 has a remainder of 12. But this isn't the only way to solve it. Say we chose to let n = 8, instead; then Part 2 says 24n = 24 * 8 = 192, and 192 divided by 36 also has a remainder of 12. The same is true for 14, and 20, and 26, and 32, and so on--after you find a value that works for Part 1, you can simply plug it in to Part 2 and it should work.</p>
<p>Maybe trying some examples would help? If so, here's a very similar problem with the numbers changed: The positive integer x has a remainder of 5 when divided by 8. What is the remainder when 3x is divided by 24?</p>
<p>Ok,.. but how do I find the remainder, sorry! :( I am stupid.</p>
<p>Not knowing how to find the remainder has nothing to do with stupidity. They're just remainders. =)</p>
<p>First off, try reading the following section of the Wikipedia article on remainders labeled "The remainder for natural numbers":
[quote]
If a and d are natural numbers, with d non-zero, it can be proved that there exist unique integers q and r, such that a = qd + r and 0 ≤ r < d. The number q is called the quotient, while r is called the remainder. The division algorithm provides a proof of this result and also an algorithm describing how to calculate the remainder.
Examples
When dividing 13 by 10, 1 is the quotient and 3 is the remainder, because 13=1</p>
<p>Oh, THANKS, GENIUS, I shall practise it right now. Huh!</p>
<p>No, I'm not a genius. I'm just a terrible procrastinator trying to put off my UT application a little longer by roaming around on random websites like this. =)</p>
<p>UT means University of Tulsa or University of Texas at Austin, Scythian?</p>
<p>Austin. I'm a Texas resident, so UT Austin's my back-up.</p>
<p>Cool, I am aiming at University of Texas at Dallas, I don't know whether this university is good or not. They offer ideal course for business and cognitive science. I have to struggle with Math a lot. Paradoxically, I am good at Modal Logic: </p>