<p>Hello everybody, i am very dumb when it comes to math and i only scored 670 so please bear with my idiotic questions :D </p>
<p>I'm practicing math a lot nowadays and I'll be asking you math geniuses about those questions that i can't get my head around. </p>
<p>1 : The sum of two integers X and Y is 56. When X is divided by Y, the quotient nis 3 and the remainder is 4. What is the value of X - Y ?</p>
<p>Note : I know i have very dumb questions, but im trying to get better so please help me ehh :P
Thanks in advance i guess ;)</p>
<p>Questions :</p>
<p>1 : The sum of two integers X and Y is 56. When X is divided by Y, the quotient nis 3 and the remainder is 4. What is the value of X - Y ?</p>
<p>A. 13
B. 14
C. 28
D. 30
E. 43</p>
<hr>
<p>2 : The various averages (arithmetic means) of three of the four numbers C, D, E, and F are calculated, and are arranged from greatest to least as follows. </p>
<pre><code> The average of C, D, and E.
The average of D, E, and F.
The average of E, F, and C.
The average of F, C, and D.
</code></pre>
<p>Which of the following correctly orders C, D, E, and F from greatest to least ?</p>
<p>A. C > D > F > E
B. D > F > E > C
C. D > E > C > F
D. E > C > F > D
E. E > D > C > F</p>
<p>1) x+y=56. If x/y is 3 with a remainder of 4 then x/y=3+4/y. Multiplying by y, x=3y+4. Solving this system of x+y=56 and x=3y+4 gives y=13 x=43 so their difference is 30 which is D.</p>
<p>2) You could just pick numbers but this is how you would solve this algebraically: all averages given have 3 terms, so if we multiplied them all by 3 we would get the sum of their terms while still preserving the inequality. so c+d+e>d+e+f>e+f+c>f+c+d. The first inequality gives c>f, the second gives d>c, the third e>d. Combining these gives e>d>c>f which is E.</p>