<p>I need some help... How do you do this question:</p>
<p>pg 411 blue book, practise test 1, section 6, Q 13?</p>
<p>I can't type it up because it involves a graph, and it's a grid question. How the hell do you do it?</p>
<p>This one too, another grid one (blue book, pg 412, Q17):</p>
<p>"In the xy-coordinate plane, the graph of x = y^2 - 4 intersects line L at (0, p) and (5, t). What is the greatest possible value of slope L?"</p>
<p>Ah nevermind I found the updated thread..</p>
<p>If you mean question 13 then its simple. </p>
<p>Since H(x) = g(2x) + 2 then H(1) = G(2) + 2
G(2) on the graph is = to 1 (remember in G(X) the 2 is the X point so go that far on the x axis and you get a y point. That is where the 1 is coming from) and then add it to 2. There is your answer (3)</p>
<p>For question 2... it is also simple.
Ok first of all this is very simple. You have the point (0,p). Now find out what P is by plugging in 0 for X into the equation. You get + or - 2. NOw plug 5 in and you get + or - 3. Now think about it. To get the biggest slope you want to have a slope thats rising fast and running slow. ANd it has to be positive. So use the point (0, -2) and (5,3) for your 2 points of the slope.</p>
<p>You should get 5/5 for ur slope or 1.</p>