<p>In triangle ABC, AB=2root2, BC=8, and angleABC=45. What is the area of triangle ABC? The answer is 8, but I can't figure out how to solve it. Please and thank you.</p>
<p>Draw a perpendicular from point A to line BC. Name the point where it intersects BC “P”, The angle PAB is 45 degrees since the sum of the angles of APB equal 180 and you know two of the angles (45 and 90). You have an isosceles right triangle with hypotenuse 2 sqrt(2) so BP and AP are 2 (apply Pythagoras theorem). The area is 1/2 base * height. The base is BC = 8, and the height is AP = 2. So you get 8.</p>
<p>Key is drawing that first line.</p>
<p>Thank you so much fogcity!</p>
<p>I have another problem… Are there any tips for these probability and arrangement type of questions? I’m always stumped.</p>
<p>What fraction of all possible arrangements of the letters A, B, C, D, and E have the letter C in the second position? The answer is 1/5.</p>