Math Help ...

Test Preparation SAT Preparation
1

<p>Hello, can somebody please help me with these math question as i can't get my head around them at all :( Thanks in advance ....</p>

<ol>
<li> A, B, C, D, E, F, G
-A list consists of all possible three-letter arrangements formed by using the letters above such that the first letter is D and one of the remaining letters is A. If no letter is used more than once in an arrangement in the list and one three-letter arrangement is randomly selected from the list, what is the probability that the arrangement selected will be DCA ?</li>
</ol>

<p>A. 1/5 B. 1/6 C. 1/9 D. 1/10 E. 1/12</p>

<ol>
<li> From a group consisting of 3 boys and 3 girls, 2 players are chosen at random for a game. What is the probability that both of the players chosen will be girls ?</li>
</ol>

<p>A. 1/15 B. 1/12 C. 1/5 D. 1/3 E. 1/2 </p>

<ol>
<li> 1. Add 3y to 2x

<ol>
<li>Multiply the sum by 2 </li>
<li>Subtract x - 2y from the product
-If the steps above are followed in order, which of the following is a simplified expression for the result ?</li>
</ol></li>
</ol>

<p>A. -4y + 3x B. y + 3x C. 4y + 5x D. 5y + 3x E. 8y + 3x </p>

<p>4.During a one-cent sale, a shopper pays the regular price for a bottle of vegetable oil and pays $0.01 for a second bottle. if the regular price of the vegetable oil is $1.89, how much per bottle does the shopper save by buying two bottles at this rate ?</p>

<p>A. $0.01 B. $0.94 C. $0.95 D. $0.96 E.$1.89 </p>

<ol>
<li><p>In an art class, there were just enough staplers, rulers and glue bottles so that every 2 students had to share a stapler, every 3 students had to share a ruler, and every 4 students had to share a glue bottle. If the sum of the number of staplers, rulers and glue bottles used by the class was 65, how many students were in the class ?</p></li>
<li><p>How many positive integers less than 1,000 are multiples of 5 and are equal to 3 times an even integer ?</p></li>
<li><p>A club is buying boxes of candy bars to sell for a fund-raiser. If each box contains c candy bars, and each member sells x bars each day, how many boxes are needed to supply enough candy bars for 3c members to sell for 5 days ?</p></li>
</ol>

<p>A. 15c^29(x) B. x/15 C. 3x/5 D. 15c^2/x E. 15x </p>

<ol>
<li>A group of people ordered 9 pizzas, each of which had 8 slices. Each person ate 2 or 3 slices. the number of people who ate 3 slices was twice the number of people who ate 2 slices, and no pizza was left. How many people were in the group ?</li>
</ol>

<p>A. 9 B. 18 C. 24 D. 27 E. 30 </p>

<ol>
<li>According to the formula F= 9/5(c)+32, if the temperature in degree Fahrenheit (F) increases by 27, by how much does the temperature in degree Celsius (C) increases ?</li>
</ol>

<p>A. 9 B. 15 C. 47 D. 48 3/5 E. 59</p>

2

<p>

</p>

<p>Answer: D. </p>

<p>Step 1: There are a total of 10 ways to arrange 3 letters given the constraints specified by the problem.</p>

<p>D, A, and _ ==> 5 possibilities (fill the blank with one of the remaining 5 letters)
D, _, and A ==> 5 possibilities </p>

<p>Step 2: The problem is asking for DCA. Probability = desired outcomes/total outcomes. </p>

<p>Therefore, the answer is 1/10. </p>

<p>

</p>

<p>Probability of two events = probability of first event * probability of second event. </p>

<p>The probability of choosing a girl the first time is 1/2. The probability of choosing a girl the second time is 2/5. </p>

<p>1/2 times 2/5 = 2/10. The answer is C. </p>

<p>

</p>

<p>Really? </p>

<p>

</p>

<p>2 students to 1 stapler
3 students to 1 ruler
4 students to 1 glue bottle</p>

<p>Common multiple: 12</p>

<p>12 students to 6 staplers
12 students to 4 rulers
12 students to 3 glue bottles </p>

<p>Ratio:</p>

<p>12 students:13 supplies :: x students::65 supplies</p>

<p>x = 60 students. </p>

<p>

</p>

<p>Equal to 3 times an even integer … hmm … 2x = even integer. Therefore, you are looking for multiples of 5 that are also divisible by 6. </p>

<p>The smallest number that fits the criteria is 30. </p>

<p>1000 / 30 = 33.333</p>

<p>Therefore, there are 33 such numbers that fit the criteria given in the problem.</p>

3

<p>IceQube : Thanks a lot for the help, appreciated…
As for 3 well yes , i actually solved that wrong, im not that smart (hence)
I only scored 640 in math , 1810 overall</p>

4

<p>Can somebody please help me with the question that “IceQube” didn’t yet answer ?</p>

5

<p>4.During a one-cent sale, a shopper pays the regular price for a bottle of vegetable oil and pays $0.01 for a second bottle. if the regular price of the vegetable oil is $1.89, how much per bottle does the shopper save by buying two bottles at this rate ?</p>

<p>The sale price for TWO bottles is $1.90
The sale price per bottle is 1.90/2 = $.95
The savings is 1.89 - .95 = $.94, choice (B)</p>

6

<p>Eminence, </p>

<p>I’m assuming that for #3 you ended up with something along the lines of 4y + 3x? You made one little mistake in your calculations that I’ve seen tested numerous times on the SAT, let me try to help.</p>

<p>Step 1: Add 3y to 2x </p>

<p>Result: 3y + 2x</p>

<p>Step 2: Multiply the sum by 2 </p>

<p>Result: 2( 3y + 2x ) = (2)3y + (2)2x = 6y + 4x</p>

<p>Step 3: Subtract x - 2y from the product. Here is where you made your mistake watch carefully.</p>

<p>6y + 4x - (x - 2y) = 6y + 4x -(+x) “-(-2y)” = 6y + 4x -x “+2y” = 8y + 3x.</p>

<p>Therefore, the answer is: 8y + 3x, E. </p>

<p>Did you see where you went wrong? Think of subtracting x - 2y as subtracting x and subtracting negative 2y, and of course minus a negative can be thought of a plus a positive. I hope that helps!</p>

<p>-iBP</p>