Math help...

Test Preparation
1

<p>I have no idea how to do this and my text book only gives me the answer, which surprisingly hasn't helped me work back through the problem. </p>

<p>Find the average rate of change of the function over the given interval.</p>

<p>h(t) = sin t; [(pi/6), pi/3]</p>

<p>Change Y= sin(pi/3) - sin(pi/6)
___________________ HOW DO SIMPLIFY THIS TO THE ANSWER?<br>
Change X= pi/3 - pi/6</p>

<p>= 3 sqrt3 - 3
___________ <== Answer
pi</p>

2

<p>my ap calc teacher always says that rate of change is code for slope. hope that helps</p>

3

<p>Always helps to know your trig.</p>

<p>sin (pi/3) = sqrt(3)/2
sin (pi/6) = 1/2</p>

<p>Average rate of change = (sqrt(3)/2 - 1/2)/(pi/3 - pi/6)</p>

<p>Simplify it and you will get the correct answer.</p>